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56x-132=4x^2
We move all terms to the left:
56x-132-(4x^2)=0
determiningTheFunctionDomain -4x^2+56x-132=0
a = -4; b = 56; c = -132;
Δ = b2-4ac
Δ = 562-4·(-4)·(-132)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-32}{2*-4}=\frac{-88}{-8} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+32}{2*-4}=\frac{-24}{-8} =+3 $
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